Average Definition and formulas
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Average Definition
Average in general means a number which represents the group of numbers is called the average number or in other words the sum (S) of all the given results/amounts/quantities/numbers when divided by the total numbers (n). The result obtained is called the average of the set of all those numbers.
Example1- Find the average of 3, 4, 5, 8, 9, 4?
Solution- n = 6
\(Average (A) = \frac {3+4+5+8+9+4}{6}\)
\(Average (A) = \frac {33}{6}\)
= 5.5
Example2- The ages of A, B and C are 32 years, 36 years and 46 years respectively, what is their average age?
Solution- n = 3
\(Average (A) = \frac {32+36+46}{3}\)
\(Average (A) = \frac {114}{3}\)
= 38
Example3- Find the average of 1, -4, 5, 6, 7, -9?
Solution- n = 6
\(Average (A) = \frac {1+(-4)+5+6+7+(-9)}{6}\)
\(Average (A) = \frac {1-4+5+6+7-9}{3}\)
\(Average (A) = \frac {6}{6}\)
= 1
Some Important formulas
1. If P goes from A to B with a speed of x km/h and comes back from B to A with a speed of y km/h, then the average speed of the whole journey is,
Average = \(\frac {2xy}{x+y}\) km/h
2. If P covers a distance from A to B at three different speeds respectively x km/hr, y km/hr and z km/hr then the average speed of the total journey,
Average Speed = \(\frac {2xyz}{xy+yz+zx}\) km/h
3. If the average of 'm' numbers is 'x' and that of 'n' numbers out of these 'm' numbers is 'y', then the average of the remaining numbers will be-
(i) Average of remaining numbers = \(\frac {mx-ny}{m-n}\) (If m > n)
(ii) Average of remaining numbers = \(\frac {ny-mx}{n-m}\) (If m < n)
4. Average of first 'n' natural numbers,
\(= (1+2+3.................+n) = \frac {n+1}{2}\)
5. Average of first 'n' odd natural numbers,
= {1+3+5+..................+(2n-1)}= n
6. Average of first 'n' even natural numbers,
= {2+4+6+..................+2n} = n+1
7. Average of squares of first 'n' natural numbers,
= (12 + 22 + 32 + 42 + ........................+ n2) = \(\frac {(n+1)(2n + 1)}{6}\)
8. Average of cubes of first 'n' natural numbers,
= (13 + 23 + 33 + 43 + ........................+ n3) = \(\frac {n(n+1)^{2}}{4}\)
9. Average of first 'n' multiples of number 'x' = \(\frac {x(n+1)}{2}\)
10. If 'a' is the average of 'n' numbers and 'b' is the average of 'm' numbers, then the average of the total numbers 'n' and 'm' will be-
Average of the total numbers 'n' and 'm' = \(\frac {na+mb}{n+m}\)
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